Files
interview/16-LeetCode Hot 100/柱状图中最大的矩形.md
yasinshaw 4247e0700d refactor: convert all LeetCode solutions to Go-only
Changes:
- Removed all Java code implementations
- Kept only Go language solutions
- Renamed "## Go 解法" to "## 解法"
- Removed "### Go 代码要点" sections
- Cleaned up duplicate headers and empty sections
- Streamlined documentation for better readability

Updated files (9):
- 三数之和.md
- 两数相加.md
- 无重复字符的最长子串.md
- 最长回文子串.md
- 括号生成.md
- 子集.md
- 单词搜索.md
- 电话号码的字母组合.md
- 柱状图中最大的矩形.md

All 22 LeetCode Hot 100 Medium problems now use Go exclusively.
Code is cleaner, more focused, and easier to follow.

Generated with [Claude Code](https://claude.ai/code)
via [Happy](https://happy.engineering)

Co-Authored-By: Claude <noreply@anthropic.com>
Co-Authored-By: Happy <yesreply@happy.engineering>
2026-03-05 12:32:55 +08:00

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Markdown

# 柱状图中最大的矩形 (Largest Rectangle in Histogram)
## 题目描述
给定 n 个非负整数,用来表示柱状图中各个柱子的高度。每个柱子彼此相邻,且宽度为 1。
求在该柱状图中,能够勾勒出来的矩形的最大面积。
## 解题思路
### 方法一:单调栈(推荐)
**核心思想:**使用单调递增栈,存储柱子的索引。当遇到比栈顶小的柱子时,弹出栈顶并计算面积。
## 代码实现
### Go 实现
```go
package main
func largestRectangleArea(heights []int) int {
stack := []int{}
maxArea := 0
n := len(heights)
for i := 0; i <= n; i++ {
h := 0
if i < n {
h = heights[i]
}
for len(stack) > 0 && h < heights[stack[len(stack)-1]] {
height := heights[stack[len(stack)-1]]
stack = stack[:len(stack)-1]
width := i
if len(stack) > 0 {
width = i - stack[len(stack)-1] - 1
}
area := height * width
if area > maxArea {
maxArea = area
}
}
stack = append(stack, i)
}
return maxArea
}
```
- LeetCode 85: 最大矩形(二维版本)
- LeetCode 42: 接雨水